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Bigwormgraphix


View Poll Results: can you finish the puzzle correctly?
0 1 4.35%
1 2 8.70%
2 14 60.87%
3 2 8.70%
4 1 4.35%
5 1 4.35%
6 0 0%
7 1 4.35%
8 0 0%
9 1 4.35%
Voters: 23. You may not vote on this poll

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Old 04-18-2012, 12:14 PM   #29
Mr_Draco


 
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Count the circles in the numbers. Depending on the font "4" is a circle.
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Old 04-18-2012, 12:15 PM   #30
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1234 = 1 has 1 circle 4
5678 = 3 has 3 circles 6 and 8
1111 = 0 has 0 circles
8111 = 2 has 2 circles 8
etc
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Old 04-18-2012, 12:19 PM   #31
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where the hell is the circle in 4?! lmao
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Old 04-18-2012, 12:20 PM   #32
SM0KE
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not circle.
enclosed area
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Old 04-18-2012, 12:22 PM   #33
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I solved it differently but still got the same answer. I over complicated the problem. Now that I look at it, the number values I gave each number equals the number of enclosures the number has lol.
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Old 04-18-2012, 12:29 PM   #34
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I still voted '9' because nobody else did. LOL
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Old 04-18-2012, 12:30 PM   #35
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OHHH I get it now.....
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Old 04-18-2012, 12:33 PM   #36
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Quote:
Originally Posted by aSSian View Post
where the hell is the circle in 4?! lmao
That's why I said depending on the font.
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Old 04-18-2012, 12:33 PM   #37
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Quote:
Originally Posted by SM0KE View Post
Do not give away the answer in the thread
Use the poll to post your answer!
Here is the puzzle...

1234 = 1
5678 = 3
1111 = 0
8111 = 2
9876 = 4
8923 = 3
2468 = 4
5555 = 0
9999 = 4
1369 = ?
First realize that each number in the problem is equal to an actual numeric value (other than itself, i.e. 5 = 0). The numbers on the left must be added to make a total value, so:
1234 = 1, then becomes 1+2+3+4 = 1

Then draw yourself a table:
1 =
2 =
3 =
4 =
5 =
6 =
7 =
8 =
9 =


Start with the easy lines (repeating numbers):
1111 = 0

5555 = 0

9999 = 4

From the first two lines, the numbers must add up to zero (0), so the numbers must be zero. The second line must be four of the same number that equals four (which is one). Fill in the table:

1 = 0
2 =
3 =
4 =
5 = 0
6 =
7 =
8 =
9 = 1


Since you now know 1 = 0, then you can plug it into the next equation:

8111 = 2, so that it is now 8+[0]+[0]+[0] =2; which means 8 = 2

1 = 0
2 =
3 =
4 =
5 = 0
6 =
7 =
8 = 2
9 = 1


Since 9 = 1, and 8 = 2, plug it into another equation:

8923 = 3, so that it is now [2]+[1]+2+3 = 3; since the [2] + [1] = 3, then 2 and 3 must be zero.

1 = 0
2 = 0
3 = 0

4 =
5 = 0
6 =
7 =
8 = 2
9 = 1


Then plug those into the first line:

1234 = 1 so that it is now [0]+[0]+[0]+4=1, which means 4 =1.

1 = 0
2 = 0
3 = 0
4 = 1
5 = 0
6 =
7 =
8 = 2
9 = 1


Now since 2 = 0, 4 = 1, and 8 = 2, plug in to find the next number:

2468 = 4, so that it is now [0]+[1]+6+[2] = 4, which means 6 = 1

1 = 0
2 = 0
3 = 0
4 = 1
5 = 0
6 = 1
7 =
8 = 2
9 = 1


Now, since we have all numbers except 7, plug the numbers into any equation with a 7:

5678 = 3, so that it is now [0]+[1]+7+[2] = 3, which means 7 = 0.

1 = 0
2 = 0
3 = 0
4 = 1
5 = 0
6 = 1
7 = 0
8 = 2
9 = 1



Finally, plug them into the final equation for your prize:

1369 = ?, which becomes [0]+[0]+[1]+[1] = 2, so the answer is 2!!!
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Old 04-18-2012, 12:34 PM   #38
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Or read above for a easier solution lol.
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Old 04-18-2012, 12:41 PM   #39
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Quote:
Originally Posted by Mr_Draco View Post
Or read above for a easier solution lol.
lol
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Old 04-18-2012, 12:46 PM   #40
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lmao or just count the cirlces LoneStarCamaro's response needs its own thread lol
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Old 04-18-2012, 01:01 PM   #41
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Quote:
Originally Posted by Mr_Draco View Post
Or read above for a easier solution lol.
Didn't realize it could be solved so easily! And I doubt it's a coincidence that both methods work...
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Old 04-18-2012, 01:05 PM   #42
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Lonestars answer is impressive..we must admit
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