04-18-2012, 12:14 PM | #29 |
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Count the circles in the numbers. Depending on the font "4" is a circle.
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04-18-2012, 12:15 PM | #30 |
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1234 = 1 has 1 circle 4
5678 = 3 has 3 circles 6 and 8 1111 = 0 has 0 circles 8111 = 2 has 2 circles 8 etc |
04-18-2012, 12:19 PM | #31 |
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where the hell is the circle in 4?! lmao
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04-18-2012, 12:20 PM | #32 |
IN THE CIRCLE
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not circle.
enclosed area |
04-18-2012, 12:22 PM | #33 |
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I solved it differently but still got the same answer. I over complicated the problem. Now that I look at it, the number values I gave each number equals the number of enclosures the number has lol.
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04-18-2012, 12:29 PM | #34 |
Booooosted.
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I still voted '9' because nobody else did. LOL
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04-18-2012, 12:30 PM | #35 |
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OHHH I get it now.....
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04-18-2012, 12:33 PM | #36 |
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04-18-2012, 12:33 PM | #37 | |
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Quote:
1234 = 1, then becomes 1+2+3+4 = 1 Then draw yourself a table: 1 = 2 = 3 = 4 = 5 = 6 = 7 = 8 = 9 = Start with the easy lines (repeating numbers): 1111 = 0 5555 = 0 9999 = 4 From the first two lines, the numbers must add up to zero (0), so the numbers must be zero. The second line must be four of the same number that equals four (which is one). Fill in the table: 1 = 0 2 = 3 = 4 = 5 = 0 6 = 7 = 8 = 9 = 1 Since you now know 1 = 0, then you can plug it into the next equation: 8111 = 2, so that it is now 8+[0]+[0]+[0] =2; which means 8 = 2 1 = 0 2 = 3 = 4 = 5 = 0 6 = 7 = 8 = 2 9 = 1 Since 9 = 1, and 8 = 2, plug it into another equation: 8923 = 3, so that it is now [2]+[1]+2+3 = 3; since the [2] + [1] = 3, then 2 and 3 must be zero. 1 = 0 2 = 0 3 = 0 4 = 5 = 0 6 = 7 = 8 = 2 9 = 1 Then plug those into the first line: 1234 = 1 so that it is now [0]+[0]+[0]+4=1, which means 4 =1. 1 = 0 2 = 0 3 = 0 4 = 1 5 = 0 6 = 7 = 8 = 2 9 = 1 Now since 2 = 0, 4 = 1, and 8 = 2, plug in to find the next number: 2468 = 4, so that it is now [0]+[1]+6+[2] = 4, which means 6 = 1 1 = 0 2 = 0 3 = 0 4 = 1 5 = 0 6 = 1 7 = 8 = 2 9 = 1 Now, since we have all numbers except 7, plug the numbers into any equation with a 7: 5678 = 3, so that it is now [0]+[1]+7+[2] = 3, which means 7 = 0. 1 = 0 2 = 0 3 = 0 4 = 1 5 = 0 6 = 1 7 = 0 8 = 2 9 = 1 Finally, plug them into the final equation for your prize: 1369 = ?, which becomes [0]+[0]+[1]+[1] = 2, so the answer is 2!!! |
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04-18-2012, 12:34 PM | #38 |
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Or read above for a easier solution lol.
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04-18-2012, 12:41 PM | #39 |
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04-18-2012, 12:46 PM | #40 |
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lmao or just count the cirlces LoneStarCamaro's response needs its own thread lol
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04-18-2012, 01:01 PM | #41 |
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Didn't realize it could be solved so easily! And I doubt it's a coincidence that both methods work...
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04-18-2012, 01:05 PM | #42 |
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Lonestars answer is impressive..we must admit
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