Quote:
Originally Posted by FlukeSS
And just for the record, we are not changing the output of the alternator, we are multiplying it and converting it from AC to DC.
That is outside of that closed system, so I believe it still follows the laws of physics so to speak.
The alternator doesn't need to power the motor, the battery does, the motor powers the alternator and drive shaft for lack of a better phrase. The alternator's low AC output is then converted to DC and with multiplied voltage and amperage, which is then fed back into the battery to offset the draw of the motor to the point the charge rate is the same or higher than the load rate.
That is also why I asked if people knew how much HP these motors produce, and how much relative draw is an alternator really going to have on a 400+ hp motor output? Do you know if it would be more or less draw compared to a regular 400+ hp Combustion engine? Or is the mechanical conversion easier in that it is more efficient than an electric motor would be?
In theory that is.
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You understand that each HP produced by motor comes from battery? There isn't any residual power in motor which could be used to charge battery.
Easy math here - let's just assume you take a motor, which will only spin the alternator (could be even motor from Tesla, powerful enough to make car fly 0-60 in 2s, doesn't matter). There will be current draw - let's say 5A at whatever voltage (F = BIl, current makes it move, not voltage, but you cannot put infinite current thru it, so we up the voltage), motor at that current flowing thru him can only output X amount of mechanical power, this X amount of mechanical power is already using around 95% of that 5A current due to losses in resistance in wiring by heat (noticed motors gets warm? that's wasted energy in heat). so now we spin the motor and have losses on the input. Just to spin. Now you connect alternator to this. You added new mechanical losses, i.e. bearings, inertia. This alternator now got your X amount of mechanical power from the motor but... minus mechanical loses, so now, let's say, mechanical loses is also 5%, so you take 5A multiply by 95% efficiency of converting electrical power to mechanical power, multiply by 95% of mechanical transfer efficiency and you are already down quite a bit. Now you start to produce electrical power again - another losses in this based on efficiency - which is somewhere in 60 - 75% (look here
https://nacfe.org/technology/high-ef...-alternator-2/).
So to recap. You take 5A and due to losses in transmission and conversion you will probably end up generating 5A * 95% * 95% * 75% = 3.38A. Now you can see that you would take much more to run alternator, than you would get out of it? And guess what. You didn't move the car an inch! You need more power than alternator will "take" to get going.
Stop talking about voltage, open systems etc... Just focus on power transfer. Voltage is your water pressure, but you need current - a water flow to get something going. you can have 100psi in you pipe but if there is no flow to follow it you will just spit somebody in the eye instead of doing anything meaningful.
Voltage multiplier works, but at relatively low power (can't get much current from it) and it's very inefficient. It's used mostly in something like electrical fence or spark plug...
Can you believe engineers? Or they are full of it?