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What’s “Fifty” mean? · 11-26-2019, 11:23 AM

Back story first.

I bought my car used, in great shape overall, but one of the rims was absolutely destroyed. Previous owner obviously loved the curb. So, I've been working with the dealership about getting it fixed. They've determined that they cannot make it look new, and it will be an obvious difference between this rim and the others. No bueno.

So, they will buy a new rim for me ($700) OR they will stroke me a check for that amount and I can purchase my own rims. I love the 1LE rims and I think they look amazing on these 50th Anniversary cars... That said, Is OEM the only way to go? I know MMR makes a replica set but I'm not sure about the quality.

This car will probably never see the track. But I still want quality. Does anyone have any experience with the replicas? I had the Z28 reps on my previous camaro and the fitment was perfect, but the gloss finish left me wanting.

Any info is much appreciated.

11-26-2019, 11:23 AM	#1
What’s “Fifty” mean? Drives: 2017 Camaro SS (50th Anniversary) Join Date: Nov 2019 Location: Philadelphia,MS Posts: 29	1LE rims question Back story first. I bought my car used, in great shape overall, but one of the rims was absolutely destroyed. Previous owner obviously loved the curb. So, I've been working with the dealership about getting it fixed. They've determined that they cannot make it look new, and it will be an obvious difference between this rim and the others. No bueno. So, they will buy a new rim for me ($700) OR they will stroke me a check for that amount and I can purchase my own rims. I love the 1LE rims and I think they look amazing on these 50th Anniversary cars... That said, Is OEM the only way to go? I know MMR makes a replica set but I'm not sure about the quality. This car will probably never see the track. But I still want quality. Does anyone have any experience with the replicas? I had the Z28 reps on my previous camaro and the fitment was perfect, but the gloss finish left me wanting. Any info is much appreciated.